(3t-2)(t+2)-3t^2=5

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Solution for (3t-2)(t+2)-3t^2=5 equation: 



(3t-2)(t+2)-3t^2=5

We move all terms to the left:

(3t-2)(t+2)-3t^2-(5)=0

We multiply parentheses ..

-3t^2+(+3t^2+6t-2t-4)-5=0

We get rid of parentheses

-3t^2+3t^2+6t-2t-4-5=0

We add all the numbers together, and all the variables

4t-9=0

We move all terms containing t to the left, all other terms to the right

4t=9

t=9/4

t=2+1/4

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